Bouyant force on a cube floating at the surface between water and oil?

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SUMMARY

A cube with a side length of 15 cm is floating at the interface of water and oil, with the oil density at 810 kg/m³. The cube is 52% submerged in water and 48% in oil. Using Archimedes' Principle, the buoyant force (Fb) is calculated as 30 N, leading to a mass of the cube determined to be 3.33 kg. This analysis demonstrates the application of fluid mechanics principles to calculate buoyancy in a multi-fluid system.

PREREQUISITES
  • Understanding of Archimedes' Principle
  • Knowledge of fluid density calculations
  • Basic algebra for solving equations
  • Familiarity with gravitational force (g = 9.8 m/s²)
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  • Learn about the effects of fluid density on buoyancy in different materials
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Students studying physics, engineers working with fluid dynamics, and anyone interested in understanding buoyancy and fluid mechanics principles.

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Homework Statement


A cube of 15 cm is floating at the surface between water and oil. The oil has a density of 810 kg/m3. If the cube floats so that it is 52% in water and 48% in the oil, what is the mass of the cube and what is the buoyant force on the cube?


Homework Equations


Archimede's Principle
Fb= densityfluidvfluidg



The Attempt at a Solution


Not sure how to find the mass of the cube when only the height of one side is given?
 
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The cube is displacing it's own weight in oil and water.
it might be simpler to think of it as two (almost ie 0.52/0.48) half cubes immersed in oil and water.
 
fb = (1000*0.52+810*0.48)*0.15^3*9.8
=30 N

mass=fb/g
=30/9=3.33
 

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