Box resting on an inclined plane

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Homework Help Overview

The discussion revolves around a physics problem involving a box resting on an inclined plane, specifically analyzing forces acting on the box, including static friction and the normal force. The problem is set in the context of mechanics, focusing on equilibrium conditions.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between static friction and normal force, questioning the reasoning behind the equation for normal force in relation to the coefficient of static friction. There is an exploration of how forces balance when the box is at rest on the incline.

Discussion Status

The discussion is active, with participants seeking clarification on the derivation of the normal force equation and its implications for the problem. There is an acknowledgment of the conditions under which static friction applies, but no consensus has been reached on the specific calculations or interpretations.

Contextual Notes

Participants are considering the effects of the incline angle and the coefficient of static friction, along with the forces acting on the box, but there may be assumptions about the system that are not fully articulated.

JamesW
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Homework Statement



A box with a mass of 22kg is at rest on a ramp inclined at 45 degrees to the horizontal. The coefficient of static friction is 0.78

determine the magnitude of the smallest force that can be applied onto the top of the box, perpendicular to the ramp if the box is to remain at rest?

Homework Equations



F=ma

The Attempt at a Solution



F f (static friction) + Fgx = 0

F n = Fgy + F a

Fa = F n - Fgy

I have viewed a thread and to calculate F n (normal force) they divided Fgx/mu static. I was wondering why this was?
 
Physics news on Phys.org
WHY IS Fn = Fgx/ mu static ?
 
because Fs=(mu static)(Fn)
 
which is valid if friction _exactly_ cancels "g sin theta" ...
 

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