Breakdown Potential of a Cylindrical Capacitor

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Homework Help Overview

The discussion revolves around calculating the capacitance and breakdown potential of a cylindrical capacitor constructed using a tall plastic drinking glass as a dielectric. The problem specifies parameters such as the dielectric constant, dielectric strength, and dimensions of the glass.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the capacitance formula and express uncertainty regarding the calculation of breakdown potential. There are attempts to use the dielectric strength multiplied by the thickness of the dielectric, but discrepancies arise regarding the correctness of this approach.

Discussion Status

Several participants have shared their calculations and expressed confusion over why their methods were marked incorrect. There is an ongoing exploration of the breakdown potential calculation, with some participants questioning the validity of their approaches and seeking clarification on the correct method.

Contextual Notes

Participants note that the dielectric strength and thickness calculations may not align with expected results, leading to further questioning of assumptions and interpretations of the problem requirements.

breez
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Homework Statement



You are asked to construct a capacitor having a capacitance near 1 nF and a breakdown potential in excess of 13000 V. You think of using the sides of a tall plastic drinking glass as a dielectric (with a dielectric constant 5.2 and dielectric strength 12 kV/mm), lining the inside and outside curved surfaces with aluminum foil to act as the plates. The glass is 14 cm tall with an inner radius of 3.17 cm and an outer radius of 3.38 cm. (a) What are the capacitance and (b) breakdown potential in kilovolts of this capacitor?

Homework Equations



C = \frac{2\pi \epsilon_0 \kappa L}{\ln \frac{b}{a}}

The Attempt at a Solution



I used the above formula to compute the capacitance, which is pretty much plug and chug.

I don't know how to compute breakdown potential though. I multiplied the dielectric strength by the thickness of the capacitor (difference in radii in mm) but that was marked wrong.

Anyone know how to properly compute the breakdown potential? This problem has me stumped.
 
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You are given a dielectric strength of 12kV/mm. Don't you just multiply that by the thickness of the glass in mm?
 
I did (3.38 - 3.17) x 10 mm x 12 kV/mm, but this was marked incorrect on the website that my online course runs on.
 
Gotta confess, I don't see why it was marked wrong. It looks fine to me. Let me know if you find out. 2.1*12kV=25.2kV total, right?
 
yeah it's strange, that's exactly what I got, but it's marked incorrect.
 
I've been presented with an extremely similar problem. I'm given a wire with a coaxial shell of equal length with a dielectric between them of strength 1x106V/m, and I subtracted the inner radius of the shell (1.5cm) from the radius of the wire (.1mm) to get .0149m of separation but when I multiply it by 1 million volts/m to get 14.9kV breakdown voltage, it's marked incorrect. Furthermore I'm supposed to calculate the maximum charge per unit length of the wire, which is obviously dependent on the capacitance (which I can calculate) and the maximum voltage (which I apparently have gotten the wrong answer for).

I also attempted to calculate the maximum charge per unit length just see if it was an error in the answer for the first portion of the question, but no dice.
 

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