Bubble chamber experiment on a K− beam

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SUMMARY

The discussion centers on the analysis of the spin and parity of the system formed by a K− beam interacting with a Λ baryon and a pion. The spin of the Λ baryon is established as 1/2, while the pion has a spin of 0, leading to a total angular momentum (J) of either 1/2 or 3/2. The parity of the system is calculated to be +1, indicating two possible states: J=1/2+ and J=3/2+. However, the discussion references the Particle Data Group (PDG) classification of the Σ(1385) as a J=3/2+ particle, raising questions about the rejection of the J=1/2+ state, suggesting further measurements may be necessary.

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Aleolomorfo
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Homework Statement
In a bubble chamber experiment on a ##K^-## beam a sample of events of the reaction ##K^- + p \rightarrow \Lambda^0 + \pi^+ + \pi^-## is selected. A resonance is detected both in the ##\Lambda^0\pi^+## and ##\Lambda^0\pi^-## mass distributions. It is called ##\Sigma(1385)##. If the study of the angular distributions establishes that the orbital angular momentum of the ##\Lambda^0\pi##system is ##L=1##, what are the possible spin parity values ##J^p##?
Relevant Equations
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Hello everybody!

Let's begin with the spin. Spin of the ##\Lambda## is ##1/2## and of the pion is ##0##:
$$ \frac{1}{2} \otimes 0 = \frac{1}{2}$$

Since I know from the homework statement that ##L=1##:
$$ \textbf{J} = \textbf{spin} \otimes \textbf{L} = \frac{1}{2} \otimes 1 = \frac{1}{2} \oplus \frac{3}{2} $$

Then the parity of the system:
$$P(\Lambda^0\pi) = P_{\Lambda}P_{\pi}(-1)^L= (+)(-)(-) = +1 $$

So there are two possibilities: ##\frac{1}{2}^+## and ##\frac{3}{2}^+##.

But from PDG ##\Sigma(1385)## is a ##\frac{3}{2}^+## particle. I do not how to reject the other possibility of ##\frac{1}{2}^+##.
Thanks in advance!
 
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This will probably need other measurements. ##\Sigma(1385) \to \Lambda \gamma## is another possible decay, for example.
The problem statement asks about possible states (plural) based on this individual measurements.
 
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