- #1
ibn_sina76
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Suppose we have four games and the probability that a player will win the game are as follows:
Game 1: 71%
Game 2: 55%
Game 3: 58%
Game 4: 16%
Suppose player b won these games with the following percentages of time:
Game 1: 100%
Game 2: 96%
Game 3: 87%
Game 4: 67%
In other words, he's a very good player. What is the probability that a player chosen at random will play these games with more skill than player b? A random player will play these games with the same skill as the average player.
I really have no idea where to begin on solving this problem. Any help would be appreciated. For the even more advanced, we can add in draws:Game 1: 71%, draw 9%
Game 2: 55%, draw 8%
Game 3: 58%, draw 6%
Game 4: 16%, draw 3%
Player b:
Game 1: 100% wins, 0% draws
Game 2: 96% wins, 3% draws
Game 3: 87% wins, 3% draws
lGame 4: 67% wins, 6% draws
Game 1: 71%
Game 2: 55%
Game 3: 58%
Game 4: 16%
Suppose player b won these games with the following percentages of time:
Game 1: 100%
Game 2: 96%
Game 3: 87%
Game 4: 67%
In other words, he's a very good player. What is the probability that a player chosen at random will play these games with more skill than player b? A random player will play these games with the same skill as the average player.
I really have no idea where to begin on solving this problem. Any help would be appreciated. For the even more advanced, we can add in draws:Game 1: 71%, draw 9%
Game 2: 55%, draw 8%
Game 3: 58%, draw 6%
Game 4: 16%, draw 3%
Player b:
Game 1: 100% wins, 0% draws
Game 2: 96% wins, 3% draws
Game 3: 87% wins, 3% draws
lGame 4: 67% wins, 6% draws
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