Calculating Building Height with Free Fall Kinematics | Spider-Man Example

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Spider-Man falls from a building, covering a distance of h, with h/4 in the last second of his fall. The discussion involves using kinematic equations to determine the height h. The correct approach separates the fall into two segments, with the first segment being three times the height of the last segment. After applying the equations and solving, participants confirm that the height h is approximately 273 meters. The calculations yield consistent results, affirming the accuracy of the solution.
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Homework Statement


Spider-Man steps from the top of a tall building. He falls freely from rest to the ground a distance of h. He falls a distance of h/4 in the last 1 second of his fall. What is h?


Homework Equations


All kinematic equations with free fall.


The Attempt at a Solution


I separated the motion into 2 cases where there was one part three times higher than the other. I made a bunch of equations that lead to nothing. Apparently I don't understand this.
 
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Which equations did you make? How do they lead to nothing?
 
Is it 276m?

What I did:

Let l = h/4

The Kinematics equation s = vit + 1/2 *at2

-l=v3l(1s) - 5*(1)2

gives (5-l) = v3

The distance spiderman moves before this is 3l, so using

vf2=vi2+2as

Vi is 0 since he starts from rest

so (5-l)^2=2*3*g*l

gives the quadratic equation l2-70x+25=0

Solving gives x = 0.358984 or 69.641

Multiply by 4 to get h.

I'm not sure if it's right though :rolleyes:
 
I made a bunch of equations that lead to nothing.

I think you just need the right 2 equations.

Focus on the time to fall. It falls 3/4 of the way in T1.

3/4*h = 1/2*g*T12

and

h = 1/2*g*T22

where T2 = T1 + 1

Solve for the total time and it's all down hill from there.
 
Thanks guys! That was a nice way to this problem LowlyPion. Also thanks physicsnoob93. I got 273m as my answer. I am pretty sure that's right after checking. Again thanks!
 
abhikesbhat said:
Thanks guys! That was a nice way to this problem LowlyPion. Also thanks physicsnoob93. I got 273m as my answer. I am pretty sure that's right after checking. Again thanks!
Not that it matters now, but I tried it both ways and they both give the same answer, 273m...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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