Buoyant force same for all object of same volume?

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The discussion revolves around the buoyant forces acting on five objects of equal volume submerged in water. While some participants argue that the buoyant forces are equal due to the volume displaced, others clarify that the forces differ based on whether the objects are fully submerged or not. When at mechanical equilibrium, objects that are not fully submerged displace less water, resulting in a smaller buoyant force. The final ranking of buoyant forces is e=b=d>a>c, emphasizing that buoyant force is linked to the volume of water displaced. The conversation highlights the importance of understanding mechanical equilibrium in buoyancy calculations.
david13579
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Rank the buoyant forces exerted on the following five objects of equal volume from the largest to the smallest. Assume the objects have been dropped into a swimming pool and allowed to come to mechanical equilibrium. If any buoyant forces are equal, state that in your ranking. (Use only ">" or "=" symbols. Do not include any parentheses around the letters or symbols.)
(a) a block of solid oak
(b) an aluminum block
(c) a beach ball made of thin plastic and inflated with air
(d) an iron block
(e) a thin-walled, sealed bottle of water


My answer? They are all equal since the buoyant force depends only on the volume displaced (whether the buoyant force is stronger or weaker than the weight of the object is irrelevant in this case I think). Cramster also says they are all equal and one of my classmates say it is equal too.

Webassign says they are not equal.
 
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When they achieve mechanical equilibrium, some of them are not fully submerged. Those not fully submerged, displace an amount of water that's' less than for those that stay submerged.
 
What's the definition of 'buoyant force' intended in the question?
 
Thanks a lot man. So in the end it comes to e=b=d>a>c
 
But don't forget the restriction that they are at mechanical equilibrium. Buoyancy force is only related to volume of water that is replaced. While in equilibrium, some of them are not completely in water, which means no water displaced.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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