Buoyant Pressure problem number 7

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    Buoyant Pressure
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SUMMARY

The forum discussion centers on a buoyant pressure problem involving a beaker filled with water, initially weighing 22.0g, and a piece of wood with a density of 0.905 kg/dm³ and a volume of 2.10 cm³. The correct approach to determine the scale reading involves calculating the mass of the wood using the formula m = density × volume, resulting in a mass of 1.905g for the wood. Therefore, the total scale reading should be 23.9g, which includes the mass of the beaker and water plus the mass of the floating wood.

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Homework Statement


When a beaker partially filled with water is placed on an accurate scale the scale reads 22.0g. If a piece of wood with a density of 0.905 kg/dm^3 and volume of 2.10 cm^3 is floating on the water, what will the scale read

Homework Equations


m=Density times volume

The Attempt at a Solution


m=density times volume
m=1000 kg/m^3 times 2.1 times 10^-8 m^3
m=2.1 times 10^-8 g
and when I add that to 22.0 g i still get 22.0 g but the answer should be 23.9 g and idk what I'm doing wrong. maybe I didn't account for the object floating on water or something like that so can someone please help me
 
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the mass of the wood is just the density of the wood times the volume of the wood.

I think 22g means the mass of the beaker & water (in grammes). So all you need to do is add the mass of the wood to this mass to get the total mass which the scale will read.

Be careful with the dm and cm units.
 

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