When a beaker partially filled with water is placed on an accurate scale the scale reads 22.0 g. If a piece of metal with a density of 3.800 kg/dm^3 and volume of 2.40 cm^3 is suspended by a thin string so that the metal is submerged in the water does not rest at the bottom of the beaker, what does the scale read
Fb=density of fluid times volume of fluid times g
Fb=F(bottom) minus F(top)
f(apparent)=F(weight) minus Fb
The Attempt at a Solution
First I used the beaker that was partially filled with water and tried solving for the force
F=.0022kg times 9.80 m/s^2
Then I Solved for force again with the density and volume given but then I just realize how does that help me so idk what 2 do please help me?