(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

When a beaker partially filled with water is placed on an accurate scale the scale reads 22.0 g. If a piece of metal with a density of 3.800 kg/dm^3 and volume of 2.40 cm^3 is suspended by a thin string so that the metal is submerged in the water does not rest at the bottom of the beaker, what does the scale read

2. Relevant equations

Density=m/v

F=mg

Fb=density of fluid times volume of fluid times g

Fb=F(bottom) minus F(top)

f(apparent)=F(weight) minus Fb

3. The attempt at a solution

First I used the beaker that was partially filled with water and tried solving for the force

F=mg

F=.0022kg times 9.80 m/s^2

F=0.02156 N

Then I Solved for force again with the density and volume given but then I just realize how does that help me so idk what 2 do please help me?

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# Homework Help: Pressure, Buoyant Force problem 8

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