C 12A 2009 - Deriving Kepler's Third Law

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SUMMARY

The discussion focuses on deriving Kepler's Third Law for two gravitationally bound stars of equal mass, m, separated by a distance d. It establishes that the orbital period is proportional to d raised to the power of 3/2. The key equations involved are F = mv²/r for centripetal force and F = Gm²/d² for gravitational force. By equating these forces, the relationship between the period and distance can be derived, confirming the proportionality constant.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with gravitational force equations
  • Knowledge of circular motion dynamics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of Kepler's Laws of planetary motion
  • Learn about gravitational interactions in binary star systems
  • Explore the implications of Newton's law of gravitation
  • Investigate the concept of center of mass in orbital mechanics
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Astronomy students, astrophysicists, and anyone interested in celestial mechanics and the dynamics of binary star systems will benefit from this discussion.

eku_girl83
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Two gravitaionally bound stars with equal masses m, separated by a distance d, revolve about their cneter of mass in circular orbites. Show that the period is proportional to d^3/2 and find the proportionality constant.

I know that in this case, F = mv^2/r and that F=Gm^2/d^2.

But where do I go from here??

Thanks for any help!
 
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eku_girl83 said:
Two gravitaionally bound stars with equal masses m, separated by a distance d, revolve about their cneter of mass in circular orbites. Show that the period is proportional to d^3/2 and find the proportionality constant.
I know that in this case, F = mv^2/r and that F=Gm^2/d^2.
But where do I go from here??
Thanks for any help!
Equate the two forces (since centripetal force is supplied by gravity) and see what you get. (Note: r = d = distance between centres of mass).

AM
 

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