Proving C1 Continuity of a Person's Path in a 2D Environment

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SUMMARY

The discussion centers on proving the C1 continuity of a person's path in a 2D environment based on a force function f(t). It concludes that as long as f(t) is finite and the set of discontinuities has measure 0, the resultant velocity will be continuous. The relationship between force, mass, and motion is established through the equation F = ma, leading to the conclusion that the integral of the force function divided by mass will yield a continuous velocity function.

PREREQUISITES
  • Understanding of C1 continuity in mathematical analysis
  • Familiarity with numerical integration techniques
  • Knowledge of classical mechanics, specifically Newton's second law (F = ma)
  • Basic concepts of measure theory related to discontinuities
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  • Study the properties of C1 continuity in mathematical functions
  • Explore numerical integration methods such as the Trapezoidal Rule and Simpson's Rule
  • Learn about the implications of discontinuities in force functions on motion
  • Investigate the application of measure theory in analyzing function continuity
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Mathematicians, physicists, and computer scientists involved in motion simulation, numerical analysis, and those studying the continuity of functions in dynamic systems.

12monkey
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Dear all,
I would appreciate if you could help me with the following problem:
A person is standing still on a 2D environment and let's assume that its initial position Xo is given. The person is moving by applying a force function over time say f(t). As a result, using numerical integration we can determine the person's acceleration, velocity and position at any time step.
My question is how we can prove that the resulting path/motion is or is not C1 continuous?
 
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12monkey said:
Dear all,
I would appreciate if you could help me with the following problem:
A person is standing still on a 2D environment and let's assume that its initial position Xo is given. The person is moving by applying a force function over time say f(t). As a result, using numerical integration we can determine the person's acceleration, velocity and position at any time step.
My question is how we can prove that the resulting path/motion is or is not C1 continuous?
As long as f(t) is finite, the resultant velocity will be continuous.
 
F= ma and v is the integral of a. That is, v is the integral of f(t)/m. As long as the set of points at which the function f(t) is discontinuous has measure 0 (no more that countably infinite is sufficient) and those discontinuities are step discontinuities (and if, as mathman says, the function is finite that is true) then its integral is continuous.
 

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