Ok so I have a problem I am not sure of the method I should use. In a recent survey, 60% of the population disagreed with a given statement, 20% agreed and 20% were unsure. Find the probability of having at least 5 person who agree in a mini-survey with 10 people. I tried to caculate the probability using a binomial distribution with n=10, p=0,2 agree and 1-p = 0,8 who either agree or are unsure, and P(X) = (n!/ (k!(n-k)!)) (p^x) ((1-p) ^(n-x)) I added p(5), p(6)... p(10) and I got p(total) = 0,0328 Is it right to use a binomial distribution in this case?