Calc Conductivity of an intrinsic semiconductor

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SUMMARY

The conductivity of an intrinsic semiconductor at room temperature can be calculated using the formula σ = neqeμe + nhqhμh, where n represents the carrier density, q is the charge per carrier, and μ is the mobility for both electrons (e) and holes (h). Given the data: carrier density (n) = 2.9 x 1019 carrier/m3, electron mobility (μe) = 0.45 m2/V s, hole mobility (μh) = 0.23 m2/V s, and charge per carrier (q) = 1.6 x 10-19 coulomb, the total conductivity can be computed by substituting these values into the formula.

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Calculate the conductivity of an intrinsic semiconductor at room temperature and from the following data:

(n)Carrier density(where electron=holes)=2.9*10^19 carrier/m^3
Electron mobility = 0.45 m^2/V s
Hole Mobility = 0.23 m^2/V s
(q)Charge per electron/hole = 1.6*10^-19 coulomb/carrier

I know that conductivity = nqu

but how do I include the e and h mobility too?
 
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What is the conductivity if there are two kinds of charge carriers?

ehild
 
ehild said:
What is the conductivity if there are two kinds of charge carriers?

ehild

?
 
From Wikipedia:

When there is more than one species (e.g., a plasma with electrons and ions, or a semiconductor with electrons and holes), the total conductivity is
σ = ∑ niμi | qi |
i

where the ith species has number density ni, charge qi, and mobility μi.

ehild
 
σ = neqeμe+nhqhμh

Where the subscripts are electron and hole respectively.

You have to account for the fact that the carriers are of opposite charge and travel in opposite directions (I think). If in doubt, you can always ask on Thursday...
 

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