[Calc II] quadratic Chebyshev approximation

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SUMMARY

The discussion focuses on the quadratic Chebyshev approximation of the function e^x on the interval [-1, 1]. The coefficients a, b, and c for the quadratic equation y = ax^2 + bx + c were calculated as a ≈ 0.53204, b ≈ 1.12977, and c = 1 by substituting specific x values into the equation. Additionally, the discussion touches on finding the quadratic truncated Taylor series centered at 0 for e^x, emphasizing the need to derive terms up to x^2 in the Maclaurin series.

PREREQUISITES
  • Understanding of quadratic functions and their coefficients
  • Familiarity with Chebyshev approximation methods
  • Knowledge of Taylor series and Maclaurin series
  • Basic calculus concepts, particularly limits and derivatives
NEXT STEPS
  • Study the derivation of Chebyshev polynomials and their applications
  • Learn how to compute Taylor series for various functions
  • Explore numerical methods for polynomial approximation
  • Investigate the convergence properties of Chebyshev approximations
USEFUL FOR

Students and educators in mathematics, particularly those studying numerical analysis, approximation theory, or calculus, will benefit from this discussion.

adillhoff
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Homework Statement


(a) The quadratic Chebyshev approximation of a function on [-1, 1] can be obtained by finding the coefficients of an arbitrary quadratic y = ax^2 + bx + c which fit the function exactly at the points (-sqrt(3)/2), 0, (sqrt(3)/2). Find the quadratic Chebyshev approximation of e^x on [-1, 1]. Approximate a, b, c to 5 decimal places.

(b) Find the quadratic truncated Taylor series centered at 0 for e^x.

Homework Equations


e^x = ax^2 + bx + c
Maclaurin for e^x


The Attempt at a Solution


For part (a), I did not know how to find the quadratic Chebyshev approximation of e^x, but I plugged in the different values of x that were given into e^x = ax^2 + bx + c in order to get 3 equations with 3 unknowns. This gives me a ≈ 0.53204, b ≈ 1.12977, and c = 1.

As for part (b), since it asks for a truncated Taylor series, I assume I need a value to stop at. I really don't feel confident doing this. Do I need to simply write the Maclaurin series for e^x?
 
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Just a guess, but maybe what's appropriate here is the Maclaurin series for your found quadratic. You could then compare with the series for exp(x).
 
maclaurin series is just a taylor series about zero, and it asks for quadratic so just find terms up to x^2
 

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