Hey guys, I'm studying for a test in calc 3 tomorrow and have run into a problem. On the practice test we have a problem "Find the length of the curve: r=theta^2, 0≤theta≤pi/2"(adsbygoogle = window.adsbygoogle || []).push({});

I know the length of a curve in polar coordinates is int(sqrt(r^2 + (dr/dtheta)^2))dtheta...but when I get to where I have to integrate sqrt(theta^4 + 4theta^2) I become very stuck. What is the procedure for handling this square root integration?

Thanks for any help.

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# Calc III Problem Integrating Sq Rt's in Arc Length Formula

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