Calc Mass KHP Req'd to React w/ 0.100M NaOH - 65 Char

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SUMMARY

The discussion focuses on calculating the mass of Potassium Hydrogen Phthalate (KHP) required to react with 35 mL of 0.100M Sodium Hydroxide (NaOH). The molar mass of KHP is established as 204.2 g/mol. Participants clarify that the reaction is a double replacement acid-base neutralization, where 1 mole of KHP reacts with 1 mole of NaOH. The correct approach involves calculating moles of NaOH and using stoichiometry to find the corresponding mass of KHP.

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Homework Statement


Calculate the mass (in grams) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

KHP = KHC8H4O4(aq)
molar mass of "KHP"= 204.2 g/mol

Homework Equations



This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

The Attempt at a Solution



It wants KHP in grams.

g/m * m/L*

See this is where I get lost. I'm sure its something simple. Also m/l = M. Just to make sure, if I have the volume (L) and the Molarity (M) to get the moles, the only thing i have to do is multiple the volume by the molarity?
 
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kremit said:
This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

You got it wrong, K won't be replaced by Na.

Try to write balanced reaction equation.

It wants KHP in grams.

Calculate moles first, then convert to grams. But you need balanced reaction equation first.

--
methods
 
thank you for the reply and groovy hair BTW. :cool: My mistake, it was the H. I had to look it over again.

KHC8H4O4(aq) + NaOH --> NaKC8H4O4 +H2O(l)

I looked over this a couple times and it looks balanced to me.

There is ...

1 Na -> 1 Na
1 K -> 1K
H+H4+H = 6 ->H4+H2= 6
C8 = C8
O4+O = 5 -> O4+O = 5

By chance is the problem:

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?
 
Last edited:
Reaction is OK - you don't have to check separately if every element is balanced, note that C8H4O42- is present on both sides, it is not much different from other groups (like SO42-) that are almost always treated as a whole.

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?

Yes, that's OK - but it is obvious now, after you have checked what is stoichiometry of the reaction. 1 mole of KHP reacts with 1 mole of NaOH.

--
methods
 
Thank you. Last question would be about converting KHP to moles.

I don't understand how to make a conversion question for that.
 
Please elaborate, no idea what you mean.

You can easily calculate number of moles of NaOH, you know they react 1:1, so number ofmoles of KHP must be identical to number of moles of NaOH.

See also

http://www.titrations.info/titration-calculation
 
Calculate the amount(in moles) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

This is what I was referring to.
 
Read my previous post, this is a simple stoichiometry.

Unless you have no idea what reation equation means. If so, please see how to read reaction equation.

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methods
 
I am a beginning chemistry student and we have only had a couple lectures on stoichiometry and molarity. I will check out your site for further information.dziękuję
 

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