Calc Mass KHP Req'd to React w/ 0.100M NaOH - 65 Char

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Discussion Overview

The discussion revolves around calculating the mass of potassium hydrogen phthalate (KHP) required to react with a specified volume and molarity of sodium hydroxide (NaOH). The conversation includes elements of stoichiometry, reaction balancing, and conversions between moles and grams, focusing on a homework problem related to acid-base neutralization reactions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant states the need to calculate the mass of KHP required based on the volume and molarity of NaOH.
  • Another participant corrects an earlier misunderstanding about the reaction, emphasizing the need for a balanced reaction equation.
  • A participant provides a balanced equation for the reaction between KHP and NaOH, asserting that it is balanced.
  • There is a discussion about the stoichiometry of the reaction, with participants noting that 1 mole of KHP reacts with 1 mole of NaOH.
  • One participant expresses confusion about converting KHP to moles and seeks clarification on how to perform this conversion.
  • Another participant suggests that the number of moles of KHP must equal the number of moles of NaOH due to the 1:1 reaction ratio.
  • A participant indicates they are a beginner in chemistry and acknowledges their limited understanding of stoichiometry and molarity.

Areas of Agreement / Disagreement

Participants generally agree on the stoichiometry of the reaction and the need for a balanced equation. However, there is some confusion regarding the conversion of KHP to moles and the specifics of stoichiometric calculations, indicating that the discussion remains unresolved in these areas.

Contextual Notes

Some participants express uncertainty about the conversion process and stoichiometry, highlighting a potential gap in understanding foundational concepts related to the problem.

kremit
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Homework Statement


Calculate the mass (in grams) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

KHP = KHC8H4O4(aq)
molar mass of "KHP"= 204.2 g/mol

Homework Equations



This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

The Attempt at a Solution



It wants KHP in grams.

g/m * m/L*

See this is where I get lost. I'm sure its something simple. Also m/l = M. Just to make sure, if I have the volume (L) and the Molarity (M) to get the moles, the only thing i have to do is multiple the volume by the molarity?
 
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kremit said:
This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

You got it wrong, K won't be replaced by Na.

Try to write balanced reaction equation.

It wants KHP in grams.

Calculate moles first, then convert to grams. But you need balanced reaction equation first.

--
methods
 
thank you for the reply and groovy hair BTW. :cool: My mistake, it was the H. I had to look it over again.

KHC8H4O4(aq) + NaOH --> NaKC8H4O4 +H2O(l)

I looked over this a couple times and it looks balanced to me.

There is ...

1 Na -> 1 Na
1 K -> 1K
H+H4+H = 6 ->H4+H2= 6
C8 = C8
O4+O = 5 -> O4+O = 5

By chance is the problem:

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?
 
Last edited:
Reaction is OK - you don't have to check separately if every element is balanced, note that C8H4O42- is present on both sides, it is not much different from other groups (like SO42-) that are almost always treated as a whole.

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?

Yes, that's OK - but it is obvious now, after you have checked what is stoichiometry of the reaction. 1 mole of KHP reacts with 1 mole of NaOH.

--
methods
 
Thank you. Last question would be about converting KHP to moles.

I don't understand how to make a conversion question for that.
 
Please elaborate, no idea what you mean.

You can easily calculate number of moles of NaOH, you know they react 1:1, so number ofmoles of KHP must be identical to number of moles of NaOH.

See also

http://www.titrations.info/titration-calculation
 
Calculate the amount(in moles) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

This is what I was referring to.
 
Read my previous post, this is a simple stoichiometry.

Unless you have no idea what reation equation means. If so, please see how to read reaction equation.

--
methods
 
I am a beginning chemistry student and we have only had a couple lectures on stoichiometry and molarity. I will check out your site for further information.dziękuję
 

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