Calc Mass KHP Req'd to React w/ 0.100M NaOH - 65 Char

  • Thread starter Thread starter kremit
  • Start date Start date
  • Tags Tags
    Grams Molarity
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
Sign up Log in
8 replies · 8K views
kremit
Messages
17
Reaction score
0

Homework Statement


Calculate the mass (in grams) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

KHP = KHC8H4O4(aq)
molar mass of "KHP"= 204.2 g/mol

Homework Equations



This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

The Attempt at a Solution



It wants KHP in grams.

g/m * m/L*

See this is where I get lost. I'm sure its something simple. Also m/l = M. Just to make sure, if I have the volume (L) and the Molarity (M) to get the moles, the only thing i have to do is multiple the volume by the molarity?
 
Physics news on Phys.org

Discussion

kremit said:
This is a double replacement reaction of the acid-base neutralization type. In other words the K will be replaced with Na and the product will have H2O in the mix.

You got it wrong, K won't be replaced by Na.

Try to write balanced reaction equation.

It wants KHP in grams.

Calculate moles first, then convert to grams. But you need balanced reaction equation first.

--
methods
 
thank you for the reply and groovy hair BTW. :cool: My mistake, it was the H. I had to look it over again.

KHC8H4O4(aq) + NaOH --> NaKC8H4O4 +H2O(l)

I looked over this a couple times and it looks balanced to me.

There is ...

1 Na -> 1 Na
1 K -> 1K
H+H4+H = 6 ->H4+H2= 6
C8 = C8
O4+O = 5 -> O4+O = 5

By chance is the problem:

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?
 
Last edited:
Reaction is OK - you don't have to check separately if every element is balanced, note that C8H4O42- is present on both sides, it is not much different from other groups (like SO42-) that are almost always treated as a whole.

mol NaOH x mol KHP/mol NaOH x g KHP/mol KHP ?

Yes, that's OK - but it is obvious now, after you have checked what is stoichiometry of the reaction. 1 mole of KHP reacts with 1 mole of NaOH.

--
methods
 
Thank you. Last question would be about converting KHP to moles.

I don't understand how to make a conversion question for that.
 
Calculate the amount(in moles) of KHP required to react completely with the NaOH in 35 mL of 0.100M NaOH.

This is what I was referring to.
 
I am a beginning chemistry student and we have only had a couple lectures on stoichiometry and molarity. I will check out your site for further information.dziękuję