- #1

kopinator

- 41

- 1

Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 6.53 J.

U= (1/2)C(dV^2)

Q= C(dV)

I found the first answer but for the 2nd part with the 6.53 J, I'm not getting the right answer.

I figured I'd use U= (1/2)C(dV^2) and solve for C. Then plug C into Q= C(dV). dV is the same for both questions.

U= (1/2)C(dV^2)

2U/(dV^2)= C

C= 1.72e-3 F

Then,

Q= C(dV)= .14964 C

That's not right answer though. What am I doing wrong?