# Calculate the energy in a capacitor's electric field

## Homework Statement

Capacitor has a charge of 0.008C. Capacity is 2 μF. Need to calculate energy of electric field. Answer: 32J

E = q2/2*C

## The Attempt at a Solution

This seems right equation, but instead of 32J I get 16J.. any ideas?

## Homework Statement

Capacitor has a charge of 0.008C. Capacity is 2 μF. Need to calculate energy of electric field. Answer: 32J

E = q2/2*C

## The Attempt at a Solution

This seems right equation, but instead of 32J I get 16J.. any ideas?

I think you are correct and the stated answer is wrong. Unless I am missing some conceptual insight, I believe they have made a calculation error.