Calculate current in a 120 VAC circuit with a series 10uF capacitor

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Discussion Overview

The discussion revolves around calculating the current in a circuit consisting of a 120 VAC, 60 Hz mains power supply connected in series with a 10uF capacitor. Participants explore the implications of this setup, including the maximum current and safety considerations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • One participant asks for help in determining the current through the circuit with a 10uF capacitor.
  • Another participant suggests calculating the capacitor's reactance at 60 Hz and using Ohm's Law for AC to find the current.
  • A participant notes that without knowing the impedance of the load, the computed current will be a maximum value.
  • One participant calculates the capacitor's impedance to be approximately 265 ohms, leading to a maximum current estimate of around 0.45A, expressing uncertainty about the correctness of this value.
  • Concerns are raised about the safety of the circuit, particularly regarding the absence of a fuse and the potential dangers associated with using a capacitor in this manner.
  • Another participant clarifies that there are additional components in the circuit, such as a full bridge rectifier, and confirms that a fuse is included for safety.

Areas of Agreement / Disagreement

Participants express varying levels of concern regarding safety and the adequacy of the circuit design. While some agree on the importance of safety measures, there is no consensus on the overall safety or effectiveness of the circuit as described.

Contextual Notes

Participants mention the need for additional information about the load to accurately determine the current. There are also unresolved concerns about the potential risks associated with the circuit design.

supak111
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Hi can someone tell me please how much current is passed though below circuit:

120 AC 60Hz mains power going through a 10uF 500v capacitor in series
 
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Calculate the reactance of the capacitor at 60 Hz, using X = 1/ 2 pi f C. Of course, get the units correct, C expressed in Farads.
Next just use "Ohms Law for AC" to find the current. I = V/X
 
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supak111 said:
120 AC 60Hz mains power going through a 10uF 500v capacitor in series
You need to finish that sentence, or attach a circuit diagram.
Without knowing the impedance of the series load, the current computed will be a maximum.
 
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Hi, maximum current was what I was after as I'm not yet sure what my load is going to be.

So capacitor impedance turn out is ~265 ohms, so my max current is ~0.45A (if I'm correct lol)

Thanks for the help
 
supak111 said:
Hi can someone tell me please how much current is passed though below circuit:

120 AC 60Hz mains power going through a 10uF 500v capacitor in series
supak111 said:
Hi, maximum current was what I was after as I'm not yet sure what my load is going to be.

So capacitor impedance turn out is ~265 ohms, so my max current is ~0.45A (if I'm correct lol)

Thanks for the help
Um, based on your past posting history at PF, this might indicate that you are considering another dangerous project. Have you gotten any training or enlisted the help of a local Mentor in your AC mains projects since your previous posts? Just looking out for you... :wink:
 
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supak111 said:
Hi, maximum current was what I was after as I'm not yet sure what my load is going to be.

So capacitor impedance turn out is ~265 ohms, so my max current is ~0.45A (if I'm correct lol)

Thanks for the help
What are you trying to do ? This is a good resource..
 
It's a simple circuit I made (which actually works pretty damn good) to restore/desulfate old car lead acid batteries. I was just wondering what the max wattage the circuit was putting out.
 
OK
 
supak111 said:
It's a simple circuit I made (which actually works pretty damn good) to restore/desulfate old car lead acid batteries. I was just wondering what the max wattage the circuit was putting out.
You made a circuit to desulfate lead acid batteries using a 120V AC mains source with no fuse and only a 10uF capacitor in series...
 
  • #10
berkeman said:
You made a circuit to desulfate lead acid batteries using a 120V AC mains source with no fuse and only a 10uF capacitor in series...
Fine... UNTIL THE CAPACITOR SHORTS! Then you have an explosion of Battery Acid.

Please put a 1Amp fuse in the circuit. Specifically a fuse, they are more reliable than a circuit breaker.

Have fun, but be safe,
Tom
 
  • #11
No there is more to the circuit... obviously a full bridge rectifier and a few other things but its not a complicated circuit.

I do have a fuse, thanks 👍
 

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