Calculate Current in a 50 Ohm Resistor from Half Wave Rectified Voltage

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Discussion Overview

The discussion revolves around calculating the average and RMS values of current through a 50 Ohm resistor when subjected to a half wave rectified voltage described by the function v(t) = 100.sin(θ). The focus is on the mathematical approach to solving this problem, including integration and the application of Ohm's law.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about how to approach the problem and seeks guidance.
  • Another participant suggests calculating the average value of the voltage by integrating the sine wave from 0 to π and dividing by π, indicating that this average voltage can then be used to find the average current using Ohm's law.
  • A different participant corrects the initial voltage function to v(t) = 100 |sin(θ)| after half-wave rectification, emphasizing the need to average the absolute value of the sine function for accurate results.
  • This participant also hints at calculating the average for a half-cycle of the sine function first.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the approach to calculating the average and RMS values, as there are differing opinions on the correct form of the voltage function to use after rectification.

Contextual Notes

The discussion highlights potential limitations in understanding the integration process and the implications of rectifying the sine function, as well as the need for clarity on definitions used in the calculations.

cleas001
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im stuck on this question and was wondering if anyone could help point me in the right direction:
a half wave rectified voltage is described by: v(t)=100.sinX
(that X is mean to be theta)
when applied to a 50 ohm resistor find the average and rms values of the current.


thanks an help is much appreciated...
a stuggling student
 
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The key word there is average. The average value of any curve equals the area of that curve divided by its length. In order words, take the integral of the sine wave from 0 to pi then divide by the length of the curve which is pi in this case. Once you find the average voltage it is possible to find the average current using ohms law.
 
Last edited:
okay i will certainly give that a good try thanks
 
cleas001 said:
im stuck on this question and was wondering if anyone could help point me in the right direction:
a half wave rectified voltage is described by: v(t)=100.sinX
No, after an ideal half-wave rectification, you will have v(t) = 100 |sin(x)|. Be sure to average the absolute value version of the excitation. Hint -- You can calculate the average for a half-cycle of the sine first...
 

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