- #1
MotionNewtion
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A car moving at 30 km/hr accelerates for 7.0 s. after which its velocity is 88 km/hr. How far does the car travel while its accelerating?
Given:
Initial Velocity : 30 km/hr
Final Velocity : 88 km/hr
Time : 7 seconds
Acceleration: ?
Distance: ?
correct me if I'm wrong
First I need to get the acceleration and convert my Vf and Vi to seconds. a = Vf - Vi / T
88km/hr - 30km/hr = 58 km/hr divide by 3600 so it will be in seconds so 0.016111111s / 7s = A
now that I have my acceleration (0.002301587286 km/s) I can either use this formula 2ad = Vf^2 - Vi^2 or D = Vi * T + 1/2 at^2
sooo...
(88 km/hr)^2 - (30 km/hr)^2 / 2(0.002301587286km/s) = Distance
so convert Vf^2 and Vi^2 to seconds again then divide by 2(0.002301587286km/s) to get distance
other solution :D
(30 km/hr) (7s) + (0.001150793643km/s) (7s)^2 = D
in this equation do I have to convert 30 km/hr to sec? If 2 of my equation are right both should have the same answer but both are different :(
Now my question is are all my equation/solution right? If not please correct it. :)
Given:
Initial Velocity : 30 km/hr
Final Velocity : 88 km/hr
Time : 7 seconds
Acceleration: ?
Distance: ?
correct me if I'm wrong
First I need to get the acceleration and convert my Vf and Vi to seconds. a = Vf - Vi / T
88km/hr - 30km/hr = 58 km/hr divide by 3600 so it will be in seconds so 0.016111111s / 7s = A
now that I have my acceleration (0.002301587286 km/s) I can either use this formula 2ad = Vf^2 - Vi^2 or D = Vi * T + 1/2 at^2
sooo...
(88 km/hr)^2 - (30 km/hr)^2 / 2(0.002301587286km/s) = Distance
so convert Vf^2 and Vi^2 to seconds again then divide by 2(0.002301587286km/s) to get distance
other solution :D
(30 km/hr) (7s) + (0.001150793643km/s) (7s)^2 = D
in this equation do I have to convert 30 km/hr to sec? If 2 of my equation are right both should have the same answer but both are different :(
Now my question is are all my equation/solution right? If not please correct it. :)