Calculate E - capacitor question

  • Thread starter Thread starter blueyellow
  • Start date Start date
  • Tags Tags
    Capacitor
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
blueyellow

Homework Statement



Consider a parallel plate capacitor with square plates of side L and distance d<<L apart. The bottom plate lies on the x-y plane, and the distance d is parallel to z. A block of dieletric material can completely fill the space between the plates.

Consider the dieletric to be composed of two materials glued together, material 1 with dieletric constant epsilon1 and dimensions 0.6L*L*d (in x, y and z directions, respectively) and material 2 with constant epsilon2 and dimensions 0.4L*L*d. The dielectric is free to move as a single block without friction along the x axis, parallel to the plates inside the capacitor, and it can also move outside the capacitor. Let us define as x the distance between the dielectric and the edge of the plates, and we can neglect the electric field outside the plates. Considering that the potential difference between two points a and b is delta V= integral from a to b of E.dl, and that D=epsilon0*epsilon(subscript r)*E, where epsilon(subscript r) is the dielectric constant, calculate the value of the electric field E and of the electric displacement field D in the region between the plates, for the three possible regions where the space is occupied by the material 1, the one with material 2, and the vacuum.

Homework Equations

 
Physics news on Phys.org
attempt at solution:

E=q/(epsilon0 *A)



E=deltaV/d

= integral from a to b of E.dl /d



E=-grad V



but all this seems to be leading nowhere.