Calculate Electrical Energy Stored in 9V Battery (120 mAh)

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Homework Help Overview

The discussion revolves around calculating the electrical energy stored in a 9V battery with a capacity of 120 mAh. Participants are exploring the conversion of battery capacity into energy units, specifically Joules.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the conversion of mAh to Ah and its impact on the energy calculation. There is discussion about the correct multiplication of voltage with either 120 mAh or its equivalent in Ah. Some participants are also clarifying the relationship between amp-hours and coulombs.

Discussion Status

The discussion is active, with participants providing insights into the units involved in energy calculations. There is a recognition of the need to convert amp-hours to coulombs for accurate energy computation, but no consensus has been reached on the correctness of the initial calculation.

Contextual Notes

Participants are navigating the requirements for expressing energy in Joules, as specified by the problem constraints, and are considering the implications of unit conversions in their calculations.

Mangastream
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Homework Statement


Calculate the electrical energy (in Joules units) which is stored in a battery with nominal voltage, 9v, and with a charge capacity of 120 mAh.


Homework Equations



J (Electrical Energy) = V (Voltage) x Ah (battery capacity)

The Attempt at a Solution



J = V x Ah
9 x 120 mAh
9 x 0.12 Ah

Answer: 1.08 Joules

Is this correct
Thank you
 
Last edited:
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The value looks way too small. How many coulombs in an amp-hour? How about 120 mAh?
 
I was wondering if 9V should be multiplied by 120 mAh or 0.120 Ah, so the correct answer then should be

9 x 120 mAh?
 
"Calculate the electrical energy (in Joules units)".

While amp-hours are a perfectly valid energy unit (if multiplied by the operating voltage), the Problem Overlords seem to require Joules as the units in this instance.

The secret to all these energy conversions is to know what the underlying units are. So an amp-hour is simply an amp (coulomb per second) times an hour (3600 seconds). So an amp hour is 3600 coulombs.

A volt is a Joule per Coulomb. So volts x amp-hours yields Joules.
 
Then why do you say that 9V x 0.12Ah = 1.08 Joules is way too small?
 
Mangastream said:
Then why do you say that 9V x 0.12Ah = 1.08 Joules is way too small?

Because 0.12Ahr = 0.12A * 3600seconds
 
Got it. Thank you.
 

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