Calculate Force Magnitude & Attractiveness of Electron Transfer

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SUMMARY

The discussion focuses on calculating the force magnitude and nature of the interaction between two neutral metal spheres after transferring 3.0x1013 electrons. The total charge (q) on one sphere is calculated as -4.8 µC using the formula q = Ne, where N is the number of electrons and e is the elementary charge (1.602x10-19C). The force (F) between the spheres is computed using Coulomb's law, resulting in a force of -0.83 N, indicating an attractive force due to opposite charges.

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dgresch
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Two neutral metal spheres are separated by 0.5m when 3.0x1013 electrons are transferred from one to the other. Calculate the resultant force magnitude and whether it is attractive or repulsive.


q=Ne
F=kq1q2/r2
I think?


q=(3.0x1013)(-1.602x10-19C)
q=-4.8uC

F=(9x109)(-4.8uC)(4.8uC)/(0.5m)2
F=-0.83N [attractive]

Does this seem correct?
 
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Looks okay!
 
thanks for the confirmation
 

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