Calculate Force on Wall from Tornado Pressure: N Units

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SUMMARY

The discussion focuses on calculating the outward force exerted on a wall by tornado pressure, specifically at a pressure of 0.46 atm. The correct approach involves converting the atmospheric pressure to Pascals (Pa) using the conversion factor of 1.013 x 10^5 Pa per atm, resulting in a pressure of 46598 Pa. The area of the wall is calculated as 34.1 m² (6.2m x 5.5m), leading to the final force calculation using the formula F = PA, yielding a force of approximately 1,590,000 N.

PREREQUISITES
  • Understanding of pressure units, specifically atmospheric pressure and Pascals.
  • Familiarity with the formula for force, F = PA, where P is pressure and A is area.
  • Basic knowledge of area calculation for rectangular surfaces.
  • Ability to perform unit conversions between atm and Pa.
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  • Study the principles of fluid dynamics related to pressure differentials.
  • Learn about the effects of tornadoes on structures and building codes for wind resistance.
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Engineers, architects, meteorologists, and anyone involved in disaster preparedness and structural integrity assessments in tornado-prone areas.

PeachyKeenZen
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Air within the funnel of a large tornado may have a pressure of only 0.46 atm.
What is the approximate outward force F on a 6.2m x 5.5m wall if a tornado suddenly envelopes the house? Atmospheric pressure is 1.013 x 10^5 Pa. Answer in units of N.

I know that P= F/A, so F=PA. I tryed just multiplying the pressure and area, but that was not correct. I also tried converting atms to Pa and then multiplying; however, that was also incorrect.

Help me, please.
 
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Welcome to PF.

What pressure did you use to find the force?
 
.46 atm.
I mulitiplied .46 and 1.013 x 10^5 to convert atm to Pa. And I got 46598 Pa and then mulitiplied that by 34.1 m^2 (6.2m x 5.5m) to solve for the force.
 

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