Calculate Frictional Force for 800N Force on 100kg Block

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SUMMARY

The discussion focuses on calculating the frictional force acting on a 100kg block subjected to an 800N force parallel to an inclined plane. The weight component acting down the incline is 500N. The frictional force is determined using the equation Ff = Fi - Wx, resulting in a calculated frictional force of 18N. The correct relationship for frictional force is established as Ff = µ × Normal Force, where µ represents the coefficient of friction.

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emilyn
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1. A force of 800N parallel to the plane is applied to a 100kg block on the plane to push it up the plane. If the component of the weight down the incline plane is 500 N, what is the frictional force?



2. Frictional force = u.Normal Force



3. Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N
 
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Welcome to PF!

emilyn said:
Frictional force = 1/Normal Force
…
Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N[/b]

Hi emilyn! Welcome to PF! :smile:

Nooo … frictional force = normal Force times coefficient of friction (µ).

(or µ = frictional force/normal force :wink:)

Try again! :smile:
 

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