Calculate Fringe Separation in Fabry-Perot Etalon

  • Thread starter Thread starter janrain
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the plate separation of a Fabry-Perot etalon used in a spectrometer setup. The setup involves illuminating one half of the slit with mercury light and the other half with white light, resulting in the observation of 20 fringes in the wavelength range of 4000 to 5000 angstroms. The key takeaway is that the number of fringes indicates the presence of 20 different wavelengths that produce constructive interference, allowing for the calculation of the plate separation using the appropriate formula.

PREREQUISITES
  • Understanding of Fabry-Perot etalon principles
  • Knowledge of constructive interference in optics
  • Familiarity with wavelength measurements in angstroms
  • Basic skills in algebra for formula derivation
NEXT STEPS
  • Study the formula for fringe separation in a Fabry-Perot etalon
  • Learn about the conditions for constructive interference in optical systems
  • Explore the impact of plate separation on fringe visibility
  • Review the principles of light interference and diffraction
USEFUL FOR

Optics students, physicists, and engineers involved in spectrometry and interference experiments will benefit from this discussion.

janrain
Messages
8
Reaction score
0
problem:
in a spectrometer, one half of the slit is illuminated with mercury light and 2nd half illuminated with white light through a fabry-perot etalon. in the wavelength range of 4000 to 5000 angstorm , 20 fringes are observed in the continuous spectrum.
calculate the plate separation of the fabry perot etalon.
 
Physics news on Phys.org
https://www.physicsforums.com/showthread.php?t=4825
 
i don't know how to proceed. don't know the formula/what needs to be done to derive it.
 
janrain said:
i don't know how to proceed. don't know the formula/what needs to be done to derive it.

Read the section on the Fabry-Perot Etalon here

http://electron9.phys.utk.edu/optics421/modules/m5/Interferometers.htm

Save this link for a nice basic description of other interferometers.

The problem is telling you that there are 20 different wavelengths between 4000 and 5000 angstroms that will give constructive interference. It sounds like your case has and air gap between two plates, and you can assume very small angle.
 
thanks a lot. that helped.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 4 ·
Replies
4
Views
5K