The discussion focuses on calculating gravitational field strength using the formula g = a = Δv/t. Given a radius of 4.76 x 10^5 m, an astronaut drops a 0.85 kg hammer from a height of 1.25 m, which takes 3 seconds to reach the ground. The average velocity is incorrectly calculated as 1.25/3, leading to confusion regarding the application of specific velocities in gravitational calculations. The correct approach requires distinguishing between average and instantaneous velocities to accurately determine gravitational acceleration.
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fdajkffk said:Homework Statement
Given Radius is 4.76*10^5 m
Astronaut drops a hammer of 0.85kg from a height of 1.25m. It takes 3s to reach the ground
What is the gravitational field strength?
Homework Equations
The Attempt at a Solution
g=a=Δv/t
v=d/t
v=1.25/3
a=1.25/3/3
But that's not the answer