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Calculate Heat of Vaporization and normal boing point (in degree C).?

  1. Feb 20, 2013 #1
    Using line equation y = -4058.7x + 16.10 with the experiment pressure measured in kPa instead of atm.

    I already solved for heat of vaporization thus:

    (-4058.7K)(-8.314 J/mol [itex]\ast[/itex]K)=heat of vaporization = 33444 J/mol = 33.44 kJ/mol.

    Also, the vapor pressure for normal boiling point:
    (1atm)(101325 Pa/1atm)(1 kPa/1000 Pa)=101.32 kPa

    I attempted to solve for T by rearranging the linear form of the Clausius-Clapeyron equation, ln Pvap = (-[itex]\Delta[/itex]H/R)(1/T) + ln [itex]\beta[/itex] into something like this (ln101.32 kPa)(-33444 J/mol [itex]\div[/itex] 8.413 J/mol * K)[itex]\div[/itex]1 - ln16.10 = T but I got something insane like 21857.7 K which even with subtracting 273 to get C is no where near close to the answer choices provided.

    Any help with the last part would be greatly appreciated.
     
  2. jcsd
  3. Feb 20, 2013 #2

    Borek

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    Staff: Mentor

    Re: Calculate Heat of Vaporization and normal boing point (in degree C

    Telling us what is x and what is y should slightly increase chances that someone will try to understand the problem and what you did.
     
  4. Feb 20, 2013 #3
    Re: Calculate Heat of Vaporization and normal boing point (in degree C

    I had to turn the assignment in this afternoon so it really doesn't matter at this point.

    Thanks anyway...
     
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