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Vapor pressure given boiling point and heat of vaporization?

  1. May 9, 2013 #1
    1. The problem statement, all variables and given/known data

    What is the vapor pressure of benzene at 50.0 C? Benzene's boiling point is 80.1 C and its heat of vaporization is 31 kJ/mol

    2. Relevant equations



    3. The attempt at a solution

    I don't want to be that guy who just says "I don't know" but.. All I know is that:

    ln P = -(Hvap)/RT + C (and I don't know what C is besides "constant.")

    and

    ln(p1/p2) = Hvap/R (T1-T2/T1T2) but this relates the vapor pressure at different temperatures..

    I am really not good at these applied things... any help is appreciated.
     
  2. jcsd
  3. May 10, 2013 #2

    Borek

    User Avatar

    Staff: Mentor

    You are right about trying to use Clausius–Clapeyron relation. What is the definition of a boiling point?
     
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