- #1

azizlwl

- 1,066

- 10

## Homework Statement

The velocity–time graph for the vertical component of the velocity of an object

thrown upward from the ground which reaches the roof of a building and

returns to the ground is shown in below. Calculate the height of the building.

http://img832.imageshack.us/img832/9528/roofr.jpg

## Homework Equations

s=vt/2

## The Attempt at a Solution

What I am thinking is that the height of the roof must be at the highest reach of the object ie. when velocity is zero. Then the total must be the total area of positive side of velocity-time graph.

## Homework Statement

The book answer is

h =1/2 × 3 × 30 −1/2 × 1 × 10 = 40m

Using above solution, it means the object goes higher than the roof.

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