Calculate how fast the car was travelling when brakes were applied

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SUMMARY

The discussion focuses on calculating the speed of a car at the moment brakes were applied, using the equation of motion and the force of friction. The limiting force was calculated as 22,500 N, leading to an acceleration of -15 m/s². By applying the equation v² = u² + 2as, the initial speed (u) was determined to be 14.5 m/s. The conversation highlights the importance of understanding the coefficient of friction, which should range between 0 and 1.

PREREQUISITES
  • Understanding of basic mechanics principles, including force and acceleration.
  • Familiarity with the equations of motion, specifically v² = u² + 2as.
  • Knowledge of friction coefficients and their implications in physics.
  • Ability to perform calculations involving Newton's second law, F = ma.
NEXT STEPS
  • Study the derivation and applications of the equations of motion in physics.
  • Explore the concept of friction and its coefficients in various materials.
  • Learn about Newton's laws of motion and their practical applications in real-world scenarios.
  • Investigate advanced topics in mechanics, such as energy conservation and momentum.
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding vehicle dynamics and braking mechanics.

chwala
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Homework Statement
see attached.
Relevant Equations
Mechanics
1717370033161.png


My query is on highlighted.


This was straightforward. I thought that coefficient of friction ought to lie between ##0## and ##1## maybe i need to check that again anyway;

##F_{lim} = 1.5 ×15000= 22, 500 N##

Using ## v^2 = u^2 +2as## and ##F=ma##

##22,500 = 1500a##

##a = -15 ##

and using ## v^2 = u^2 +2as##

##0 = u^2 + (2 ×-15×7)##

##u^2 = 210##

##u = 14.5 m/s## correct to one decimal point.
 
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chwala said:
Homework Statement: see attached.
Relevant Equations: Mechanics

I thought that coefficient of friction ought to lie between 0 and 1
A common misunderstanding.
 
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