Calculate how fast the car was travelling when brakes were applied

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The discussion revolves around calculating the speed of a car when brakes are applied, using the coefficient of friction and basic mechanics equations. The limit force was calculated as 22,500 N, leading to an acceleration of -15 m/s². By applying the equation v² = u² + 2as, the initial speed (u) was determined to be 14.5 m/s. There was a mention of the coefficient of friction needing to be between 0 and 1, highlighting a common misunderstanding in physics. The calculations and concepts presented clarify the relationship between force, acceleration, and speed in braking scenarios.
chwala
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Homework Statement
see attached.
Relevant Equations
Mechanics
1717370033161.png


My query is on highlighted.


This was straightforward. I thought that coefficient of friction ought to lie between ##0## and ##1## maybe i need to check that again anyway;

##F_{lim} = 1.5 ×15000= 22, 500 N##

Using ## v^2 = u^2 +2as## and ##F=ma##

##22,500 = 1500a##

##a = -15 ##

and using ## v^2 = u^2 +2as##

##0 = u^2 + (2 ×-15×7)##

##u^2 = 210##

##u = 14.5 m/s## correct to one decimal point.
 
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chwala said:
Homework Statement: see attached.
Relevant Equations: Mechanics

I thought that coefficient of friction ought to lie between 0 and 1
A common misunderstanding.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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