Calculate how fast the car was travelling when brakes were applied

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The discussion revolves around calculating the speed of a car when brakes are applied, using the coefficient of friction and basic mechanics equations. The limit force was calculated as 22,500 N, leading to an acceleration of -15 m/s². By applying the equation v² = u² + 2as, the initial speed (u) was determined to be 14.5 m/s. There was a mention of the coefficient of friction needing to be between 0 and 1, highlighting a common misunderstanding in physics. The calculations and concepts presented clarify the relationship between force, acceleration, and speed in braking scenarios.
chwala
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Homework Statement
see attached.
Relevant Equations
Mechanics
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My query is on highlighted.


This was straightforward. I thought that coefficient of friction ought to lie between ##0## and ##1## maybe i need to check that again anyway;

##F_{lim} = 1.5 ×15000= 22, 500 N##

Using ## v^2 = u^2 +2as## and ##F=ma##

##22,500 = 1500a##

##a = -15 ##

and using ## v^2 = u^2 +2as##

##0 = u^2 + (2 ×-15×7)##

##u^2 = 210##

##u = 14.5 m/s## correct to one decimal point.
 
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chwala said:
Homework Statement: see attached.
Relevant Equations: Mechanics

I thought that coefficient of friction ought to lie between 0 and 1
A common misunderstanding.
 
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