chwala
Gold Member
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- Homework Statement
- see attached.
- Relevant Equations
- Mechanics
My query is on highlighted.
This was straightforward. I thought that coefficient of friction ought to lie between ##0## and ##1## maybe i need to check that again anyway;
##F_{lim} = 1.5 ×15000= 22, 500 N##
Using ## v^2 = u^2 +2as## and ##F=ma##
##22,500 = 1500a##
##a = -15 ##
and using ## v^2 = u^2 +2as##
##0 = u^2 + (2 ×-15×7)##
##u^2 = 210##
##u = 14.5 m/s## correct to one decimal point.