The problem involves calculating the initial speed of a ball thrown vertically from ground level to a height of 14 meters, caught 3 seconds later. The context is kinematics, specifically dealing with projectile motion under the influence of gravity.
Participants have provided guidance on using the acceleration due to gravity and have explored the implications of sign conventions in their calculations. There is ongoing clarification regarding the correct application of the formula and the values to be used.
There is some confusion regarding the relationship between time and acceleration, as well as the correct sign for the acceleration due to gravity. Participants are working within the constraints of the problem's parameters and the physics involved.
It's a projectile. You should know the acceleration.patelneel1994 said:How do I find acceleration?
No. Where in the world did that come from?patelneel1994 said:Is it 3 ms-2?
The acceleration is constant.patelneel1994 said:I thought time and acceleration some how are related, which are not.
Of course you should use the acceleration due to gravity!Could we use gravity, which is 9.79 m/s2?
No. Why would you think that?patelneel1994 said:So if we solve using acceleration, then a = 0 right!
You have the right formula. For the acceleration, use the acceleration due to gravity.How can I solve using gravity? Is there any different formula?
What's the sign of the acceleration? Which way does gravity act?patelneel1994 said:Sorry a = 9.78 m/s^2
Use a proper sign convention in your equation. Let 'up' be positive and 'down' be negative.patelneel1994 said:Gravity pull an object down towards the ground. a = 9.78 ms-2!