Calculate Iridium Atom Radius | Material Science

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SUMMARY

The discussion focuses on calculating the radius of an iridium atom, which has a face-centered cubic (FCC) crystal structure, a density of 22.4 g/cm³, and an atomic weight of 192.2 g/mol. To determine the atomic radius, one must first calculate the atomic density using the given density and atomic weight, then relate this to the volume of the unit cell and the number of atoms in the FCC structure. The relationship between the cell edge length and atomic radius is crucial, as well as understanding the significance of the face diagonal in the FCC cell.

PREREQUISITES
  • Understanding of FCC crystal structure
  • Knowledge of atomic weight and density calculations
  • Familiarity with Avogadro's number
  • Basic principles of unit cell volume and atomic density
NEXT STEPS
  • Research the calculation of atomic radius in FCC structures
  • Learn about the significance of the face diagonal in FCC unit cells
  • Study the relationship between atomic density and unit cell volume
  • Explore the application of the Pythagorean theorem in crystal structure calculations
USEFUL FOR

Material science students, chemists, and anyone involved in crystallography or solid-state physics will benefit from this discussion, particularly those focused on calculating atomic dimensions in crystalline materials.

nebs92
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Hi I am in a material science class and one of my homework questions states:

"Calculate the radius of an iridium atom,given that Ir has an FCC crystal structure, a density of 22.4g/cm^3,and an atomic weight of 192.2g/mol."

I think I have to use the Pythagorean theorem somewhere but my teacher went off on some tangent about something unrelated when he was talking about this. Any help will be greatly thanked!
 
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nebs92 said:
Hi I am in a material science class and one of my homework questions states:

"Calculate the radius of an iridium atom, given that Ir has an FCC crystal structure, a density of 22.4g/cm^3,and an atomic weight of 192.2g/mol."

I think I have to use the Pythagorean theorem somewhere but my teacher went off on some tangent about something unrelated when he was talking about this. Any help will be greatly thanked!
One uses the mass density and the atomic weight to determine the atomic density. Dividing by Avogadro's (or Loschmidt's) number, one obtains the volume of a metals unit cell, then one must relate this to the number of atoms in the unit (crystal) cell and the cell dimensions to the atomic radius or diameter. It's relatively simple and straightforward for cubic structures.

How many atoms in an FCC cell?

What is the relationship of the length of the cell edge or lattice parameter to the atomic radius on an FCC metal?

Or what is significant about the face diagonal of the FCC cell?

Similar, what is significant about the major diagonal (opposite corner, not the same face) for a bcc cell?
 

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