Calculate Joules Used by 100W Light Bulb in 2 Hours

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SUMMARY

The energy consumed by a 100W light bulb over a duration of 2 hours is calculated to be 720,000 Joules. This is derived using the formula E = P * T, where P represents power in Joules per second and T represents time in seconds. The calculation confirms that 100 Watts multiplied by 7200 seconds results in 720,000 Joules. The discussion emphasizes the importance of using consistent equations and variables to avoid errors in calculations.

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  • Understanding of basic physics concepts, specifically power and energy.
  • Familiarity with the formula E = P * T for calculating energy.
  • Knowledge of unit conversions, particularly between hours and seconds.
  • Experience with using scientific calculators, such as Texas Instruments models.
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  • Learn about unit conversions, especially converting hours to seconds for energy calculations.
  • Explore the functionalities of Texas Instruments calculators for solving physics equations.
  • Study common mistakes in algebraic manipulation of formulas in physics problems.
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This discussion is beneficial for physics students, educators teaching energy concepts, and anyone interested in understanding electrical power consumption calculations.

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How much energy in Joules is used by a 100 W light bulb in 2 hours?

W=\frac{J}{s}

100 W=\frac{x_{j}}{7200_s}

720000=Joules

My teacher said I probably got the right answer but I did the wrong work. I think I did so too. Can some1 help me out?

Thanks
 
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DB said:
How much energy in Joules is used by a 100 W light bulb in 2 hours?

W=\frac{J}{s}

100 W=\frac{x_{j}}{7200_s}

720000=Joules

My teacher said I probably got the right answer but I did the wrong work. I think I did so too. Can some1 help me out?

Thanks
Your answer is "correct". However, it's better to work problems using equations with variables representing the various quantities.
In words:
{Power} = {Energy}/{Time}
Now let {P = Power (in J/sec)}, {E = Energy (in J)}, and {T = Time (in sec)}, so that:
P = E/T
::: ⇒ E = P*T

For your problem:
P = (100 Watts) = (100 J/sec)
T = (2 hours) = (7200 sec)
E = (100 J/sec)*(7200 sec) = (720000 Joules)


~~
 
Last edited:
DB said:
How much energy in Joules is used by a 100 W light bulb in 2 hours?

W=\frac{J}{s}

100 W=\frac{x_{j}}{7200_s}

720000=Joules

My teacher said I probably got the right answer but I did the wrong work. I think I did so too. Can some1 help me out?

I would argue that your approach is better than the teacher's approach; especially when using a Texas Instruments calculator. TI calculators have an equation solver, so you don't actually need to manipulate the formula. The less you screw with an equation, the less likely you are to make silly algebra errors.
 
Last edited:
Check out my method of writing formulas

http://myfiles.dyndns.org:8080/math/shawn_equation_style.jpg


Notice how nothing is moved around from the original formula. The value I'm trying to find isn't even isolated.
You're in a physics class, so do physics. Math is for the losers in the math class :-p
 
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