Calculate Launch Velocity: Spring Force with 80kg Mass and 2kg Object

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Homework Help Overview

The discussion revolves around a physics problem involving a spring and two different masses. The original poster describes a scenario where an 80.0 kg mass compresses a spring by 20 cm, and later, a 2.0 kg object is launched after compressing the same spring by 5.0 m. The goal is to determine the launch velocity of the 2.0 kg object.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using energy principles to find the spring constant and question how to identify the relevant variables for the energy equation. There is uncertainty about which values to use for height and compression in the calculations.

Discussion Status

Participants are actively engaging with the problem, exploring different approaches to find the spring constant and discussing the application of conservation of mechanical energy. Some guidance has been offered regarding the relationship between the variables involved.

Contextual Notes

There is a lack of explicit values for certain variables, such as height and compression, which participants are trying to clarify. The original poster expresses confusion about the problem setup and the necessary calculations.

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When a 80.0kg mass is placed (not dropped) on topof a spring, the spring is depressed by 20 cm. The same spring is then used to launch a 2.0 kg object vertically. If the spring is compressed 5.0 m by pushing it down, and the object is then placed on top and the spring released, what will be the launch velocity of the 2.0kg object? Draw and label the force diagram as part of your answer.

I do not really ge twhat I am supposed to do here and I have no clue where to start. Any help would be greatly appreciated!
 
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try using energy to solve for the spring constant.
 
But how would I find the energy?
 
[tex]mgh = \frac {1}{2} kx^2[/tex]
 
But what would be my h and what would be my x?
 
I am not given the h or the x am I?
 
The x is the amount that the spring is compressed. In this case the h is the same as the x, because the only change in the masses height is because off the compression of the spring.
 
Ok thanks!
 
Wait, am I using the 8o.o kg and the 20cm or the 1.0kg and the 5.0m?
 
  • #10
80.0kg and the 20cm
 
  • #11
so then I get 68.6 for k but then what do i do with that?
 
  • #12
Force = kx
F/x = k

what is the Force...check your units.
 
  • #13
I am not sure what you mean?
 
  • #14
once you find the spring constant, you can use it for the second part of the problem.
 
  • #15
Hint: Conservation of mechanical energy.
 

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