Calculate Limit - Wolfram Alpha

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The discussion focuses on calculating a limit using Wolfram Alpha and involves rewriting a series as a Riemann sum. Participants emphasize the importance of expressing the series in the form of a Riemann sum to facilitate the limit calculation. The limit can be evaluated as the integral of the function f over the interval from 0 to 1. One user expresses gratitude for the helpful tip that simplified the process. The conversation highlights the connection between limits, series, and integrals in calculus.
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Calculate the limit of :

[PLAIN]http://www3.wolframalpha.com/Calculate/MSP/MSP3119g718e25g367ahi000057f7afh4fdhed60b?MSPStoreType=image/gif&s=9&w=150&h=57

Thanks for the help.
 
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Hi puzzek! :smile:

Can you rewrite this series to a Riemann sum. That is, rewrite it to the form

\sum_{k=1}^{+\infty}{f(\frac{k}{n})\frac{1}{n}}

for a function f. Wshy should you do this? Well, since you know that

\lim_{n\rightarrow +\infty}{\sum_{k=1}^{+\infty}{f(\frac{k}{n})\frac{1}{n}}}=\int_0^1{f(x)dx}
 
micromass Thank you!

your tip made it a lot easier !
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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