How to Find the Volume of a Rotating Solid?

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SUMMARY

The discussion focuses on calculating the volume of a solid of revolution formed by rotating the region defined by the function f(x) = 2 sin x over the interval [0, π] around the line y = -1. The correct volume formula is derived using the integration method: V = π∫(2sin(x) + 1)² dx. Participants express confusion regarding the definition of the region and the choice of the boundary line for rotation, emphasizing the importance of clearly defining the area of interest in volume calculations.

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  • Understanding of solid of revolution concepts
  • Familiarity with integration techniques
  • Knowledge of the sine function and its properties
  • Ability to interpret graphical representations of functions
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  • Study the method of disks/washers for volume calculations
  • Learn about the application of definite integrals in geometry
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  • Investigate the implications of rotating around different axes
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Students in calculus, mathematics educators, and anyone interested in mastering volume calculations of solids of revolution.

DrAlexMV
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Homework Statement


Region: f(x) = 2 sin x on the interval [0, π]. Find the volume of
the 3D solid obtained by rotating this region
about the dashed line y = −1.

Homework Equations



Integration of pi∫(2sin(x) + 1)^2 dx

The Attempt at a Solution



http://www3.wolframalpha.com/Calculate/MSP/MSP85361a550f47a75i0g7800002h3g026g9d9ieg7f?MSPStoreType=image/gif&s=3&w=301&h=35

That does not seem to work. I am completely baffled as to what I am doing wrong.
 
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f(x) = 2 sin x on the interval [0, π] does not define a region. It defines a curve and two limits on the x coordinate. You seem to be assuming the remaining boundary is the line y = -1, but why that rather than, say, the x axis?
 

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