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Calculate linear momentum of earth

  1. May 6, 2015 #1
    1. The problem statement, all variables and given/known data
    The mass of the Earth is 5.972 x 10^24 kg and its orbital radius is an average of 1.496 x 10^11 m. Calculate its linear momentum.

    2. Relevant equations

    3. The attempt at a solution
    I am not sure how to start?
    mass= 5.972*10^24 kg
    Radius(to travel around sun): 1.496*10^11 m
    To find:
    Tangential velocity and then use the p=mv formula??
    Last edited: May 6, 2015
  2. jcsd
  3. May 6, 2015 #2


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    Yes. How far does the earth travel in going around the sun once? How long does this take?
  4. May 6, 2015 #3
    Oh, sorry I missed that we need time and then we can assume that charts travels in a circle so we find displacement then velocity....

    So here is what I did:
    Time=365 days*24hour*60min*60sec= 31,536,000 sec
    Distance traveled= 2*pi*R= 9.4*10^11 m
    Velocity= 29,806 m/s (this is tangential velocity so it is a linear velocity)
    Momentum=mv= 1.78*10^29 kg*m/s
  5. May 6, 2015 #4


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    That looks right.
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