The discussion focuses on calculating the load capacity of a mild steel column with a cross-section of 100mm by 50mm, using a safety factor of 6. The formula applied is W = A * δ, where δ represents the allowable stress. The correct calculation yields a safe load of approximately 400 kN, considering the ultimate stress for mild steel is 470 N/mm². The initial miscalculation of 391.7 N was clarified to reflect the correct unit conversion and safety factor application.
PREREQUISITESStructural engineers, civil engineering students, and professionals involved in designing and analyzing steel structures will benefit from this discussion.
you mean 78 N/mm^2John78 said:Homework Statement
A mild steel column has a cross section of 100m by 50mm. Assuming a safety factor of 6 calculate the load that it can safely support
Homework Equations
W=A*δ
The Attempt at a Solution
δ=470 N/mm2*0,1667= 78,34 mm2
about 400 kN, yes, assuming a short column and a FS of 6 against what appears to be an ultimate stress of a mild steel.A=100mm*50mm=5000mm2
W =5000* 78,34=391700/1000=391,7 N??