Calculate Magnitude of q & Electric Field Strength for Na+ & Cl- Ions: 0.24nm

[sci0x]

Question The separation between Na+ and Cl- ions in a molecule is 0.24nm. They are point charges of +q and -q and force of attraction between them is 4.0x10^-19N.

a) Get the magnitude of the q
Possible Answer: Do I just use Coloumbs law? I got 1.03x10^-14C

b) What is the electrical field strength (in magnitude and direction) at the mid-point of the molecule?
Possible Answer: Not sure what to do here? I'm thinking maybe its 0 but that would just be too easy.

Thanks in advance!?

 

[Doc Al]

a) Get the magnitude of the q
Possible Answer: Do I just use Coloumbs law? I got 1.03x10^-14C

I didn't check your answer, but using Coulomb's law is all you need to do.

b) What is the electrical field strength (in magnitude and direction) at the mid-point of the molecule?
Possible Answer: Not sure what to do here? I'm thinking maybe its 0 but that would just be too easy.

You just found the charges in part a, so now find the field strength. What's the field at a distance from a point charge? (Hint: the charges have opposite signs, so the fields don't cancel.)