Calculate Mass of Au Produced from 0.0500 mol Au2S3

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SUMMARY

The discussion centers on calculating the mass of gold (Au) produced from the complete reduction of 0.0500 mol of gold(III) sulfide (Au2S3) using excess hydrogen (H2). The participant initially calculated the mass as 19.7 grams based on the molar mass of gold (197 g/mol) but questioned the accuracy of this result after finding it inconsistent with a textbook answer. The correct approach confirms that 19.7 grams is indeed the accurate mass of Au produced from the given amount of Au2S3.

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  • Understanding of stoichiometry in chemical reactions
  • Familiarity with molar mass calculations
  • Knowledge of reduction reactions involving metals
  • Basic principles of chemical equations
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  • Review stoichiometric calculations for reduction reactions
  • Study the properties and reactions of gold(III) sulfide (Au2S3)
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Homework Statement


What mass of Au is produced when 0.0500 mol of Au2S3 is reduced completely with excess H2?


Homework Equations





The Attempt at a Solution



.100 mol Au3+ x 197/1 = 19.7 g

19.7 g is apparently wrong though according to the book; what am I doing wrong?
 
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Look for a new book, 19.7g is the correct answer.
 

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