Calculate Mass of Unknown Planet with Physics B Ques.

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An astronaut on an unknown planet with a radius of 3560 m jumps with an initial speed of 3.00 m/s, reaching a height of 0.50 m. To find the planet's mass, the acceleration due to gravity must be calculated using the motion of the astronaut. The formula vf² = v₀² + 2aΔX is suggested to determine acceleration, leading to a calculation of a = 9 m/s². This value seems inconsistent given the planet's radius, prompting speculation about the planet's nature, such as it being a neutron star. Ultimately, the mass can be calculated using the formula M = gr² / G once the correct acceleration is confirmed.
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Homework Statement


An astronaut lands on an unknown planet with a radius of 3560 m. When she jumps upward with an initial speed of 3.00m/s she rises to a height of 0.50 m. What is the mass of the planet?

Homework Equations


d = rt
x = x0 + v0t + \frac{1}{2}at2
M = gr2 / G

The Attempt at a Solution


0.5 m / (3.0m/s) = \frac{1}{6}s
0.5 = 0 + 3\frac{1}{6}s + \frac{1}{2}a\frac{1}{6}2
0.5 = \frac{1}{2} + \frac{1}{2}a\frac{1}{36}
a = 0 m/s2?

I have no idea what to do. please help me.
 
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You need to get the value of the acceleration from the information given about the motion of the astronaut. Look for an accelerated motion formula with distance but not time in it. Put in the numbers and solve for a.

Your calc getting 1/6 second looks like a d = vt, which does not apply to accelerated motion.
 
In order to find the acceleration(gravity of the planet in this case) of the astronaut, I used following formula.

vf2 = v02 + 2a\DeltaX

If I solve for 'a', then I get

a = (vf2-vo2 / 2\DeltaX

I pluged in the numbers,

a = (9m/s) / 2(0.5 m) = 9 m/s2

which doesn't make sense because the radius of the planet is only 3560 m.

please help me what to do next.
 
I got 9, too. Maybe it is a neutron star or something.
Use this value of g to find M. Your formula M = gr2 / G should do it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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