Calculate melting point of ice under pressure

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SUMMARY

The discussion focuses on calculating the melting point of ice under a pressure of 6000 kPa using the Clausius–Clapeyron relation. Participants emphasize the importance of using the densities of solid and liquid water, approximately 920 kg/m3 and 1000 kg/m3, respectively, to determine the volume change during melting. The correct approach involves applying the melting version of the Clausius–Clapeyron equation, not the evaporation version, to find the change in temperature (delta T). The final melting point can be calculated by adjusting the standard melting point of water with the derived delta T.

PREREQUISITES
  • Understanding of the Clausius–Clapeyron relation
  • Knowledge of density calculations for solids and liquids
  • Familiarity with thermodynamic concepts such as heat of fusion
  • Basic algebra for rearranging equations
NEXT STEPS
  • Study the Clausius–Clapeyron relation specifically for phase changes
  • Learn how to calculate volume changes using density values
  • Research the heat of fusion for various substances
  • Practice solving problems involving pressure and phase transitions
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Students in chemistry or physics, educators teaching thermodynamics, and anyone interested in the effects of pressure on phase changes of water.

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Homework Statement


The density of solid water is approximately 920 kg m^-3 and that of liquid water is 1000 kg m^-3. Calculate the melting point of ice under a pressure of 6000 kPa.


Homework Equations



This is my problem. How do I approach this? I don't see any relevant equations in my textbook.


The Attempt at a Solution


See 2.
 
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Clausius–Clapeyron relation perhaps?
 
Last edited by a moderator:
Borek said:
Clausius–Clapeyron relation perhaps?

Not really. That has to do with pressure, but how does the density fit in?
 
Use it to calculate volume change.
 
Last edited by a moderator:
Borek said:
Use it to calculate volume change.

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I'm not following. Use the density to calculate volume change? Or use the Calpeyron equation to calcululate it? The equation I have found so far is:

delta(ln p) = delta_vapH/RT^2 * delta T

Is this correct? Thanks
 
No, this is version for evaporation, you need version for melting. Use given densities to calculate volume change.

See wikipedia article on Clausius–Clapeyron relation.
 
Borek said:
No, this is version for evaporation, you need version for melting. Use given densities to calculate volume change.

See wikipedia article on Clausius–Clapeyron relation.

So, like their example at the bottom of the page...

7ccf0e9ffa7dc258672182cdaa1060e4.png


and then rearrange and solve for deltaT and I get -0.4438K which doesn't mke much sense?
 
What is delta T?
 
Borek said:
What is delta T?

Change in temperature (melting temp).
 
  • #10
And what was delta T you calculated?
 
  • #11
Borek said:
And what was delta T you calculated?

Ok, so it would be: melting point water - (-0.4438K) for a final melting point?
 
  • #12
That would sound logical.
 
  • #13
Borek said:
That would sound logical.

Awesome! Thanks, I appreciate the help!
 
  • #14
i have something like it:

The densities of ice and liquid water at 1atm (101,325KPa) and 0oC are
917Kg/m3 and 999,8Kg/m3, respectively. The heat of fusion of water is 334720J/Kg.
Calculate the melting point of ice at 0,5atm (50,662KPa) and 101atm (10,2338MPa).

i don't know how i find "delta"H
 
  • #15
What IS delta H?
 

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