Calculate molar conductivity of Co(NH3)4CO3]NO3?

[amit25]

Homework Statement

This was determined from an experiment,where the resistance of 0.02M of KCl was to be determined
[KCl]=0.02M conductance=2.86ms L=0.002768ohm^-1 to obtain k

Co(NH3)4CO3]NO3 :
conductance: 1.923ms concentration of cobalt complex: 0.002M

Homework Equations

k=RL Molar conductivity=1000L/M

The Attempt at a Solution

k=RL k=(2.86ms)(0.002768ohm^-1)
k=0.00791648 ms/cm ohm^-1

L=k/R =0.00791648ms/cm ohm^-1/0.1923ms
L=0.041167cm x ohm^-1
molar conductivity=1000(0.041176)/0.002M
=19712.8cm Xohm^-1 / M x 1m/100cm
=197.1 m x ohm^-1/MNot sure if i did it correctly

 

[Borek]

It won't hurt if you will name your variables and describe the data you were given.

We could try to guess them from the units and the way you are using them, but - speaking for myself - I have much better brain teasers to play with.