1. The problem statement, all variables and given/known data A copper sheet of thickness 2.37mm is bonded to a Aluminum sheet of thickness 1.29mm. The outside surface of the copper sheet is held at a temperature of 100.0°C and the Aluminum sheet at 24.5°C. a) Determine the temperature of the copper-aluminum interface. b) How much heat is conducted through 1.00m2 of the combined sheets per second? LCu = 0.237 cm TCu = 373 K κCu = 385 (W/m*K) LAl = 0.129 cm TAl = 297.5 K κAl = 205 (W/m*K) 2. Relevant equations PCond=Q/t=Aκ(ΔT/L) 3. The attempt at a solution Part a) Now the question doesn't say anything about the sheets being in a steady state so I spent a lot of time trying to solve it without assuming that. After a while I gave up and just assumed it to be in a steady state and I solved for the temperature in between the sheets. My answer was correct AκCu((TCu-Tx)/LCu) = AκAl((Tx-TAl/LAl) After some careful rearranging I solved for Tx Tx=335.665 K So to assume a steady state is the only way I see to have all the necessary information to find the temperature of the copper-aluminum interface. Can someone explain what in the question tells me that it is in a steady state? Part b) I would have the calculate the thermal conductivity rate for this dual sheet interface, then use the thermal conductivity equation, set it equal to the thermal conductivity rate I just calculate it with a length of 1.00 m2. To do this I need to know the face area of the sheets, but I am only given the thickness. I can't cancel the face area value since I am not setting it equal to anything with that same value on the other side. I feel that I am so close to the answer. Any help is appreciated. Thanks.