Calculate Molar Volume of Vapour-Liquid System with X=0.2

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SUMMARY

The molar volume of a saturated vapour-liquid system can be calculated using the formula V = Vf(1-X) + VgX, where Vf is the molar volume of the condensed phase, Vg is the molar volume of the vapour phase, and X is the quality. In a closed system containing only water at 25°C with a vapour pressure of 3168 Pa and a quality of 0.2, the calculation requires understanding the definitions of quality and specific volume. Quality is defined as x = mv/(mv + ml), where mv is the mass of vapor and ml is the mass of liquid. The specific volumes of both phases must be determined based on the temperature and pressure conditions.

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Ive been trying to figure this one out for too long,please help :s !

Molar volume of a saturated vapour-liquid system is given by V=Vf(1-X) + VgX,
where Vf=molar vol. of condensed phase
Vg=molar volume of vapour phase
X=quality
A given closed system contains only water in VLE at 25oC. Vapour pressure of water at this temp. is 3168 Pa.

Calculate the molar volume of the system if the quality is 0.2.

Any ideas??
Thanks
 
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This seems like a homework problem.

Firstly, one must understand the definition of quality, x.

x=mv/(mv + ml)

where mv = mass of vapor and ml = mass of liquid

So quality is defined on a mass basis, which can be related to moles.

Also the volume of either liquid or vapor is simply mass*specific volume and liquid and vapor have different specific volumes depending upon temperature and pressure. Specific volume is simply the reciprocal of density.
 

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