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## Homework Statement

Consider the following aqueous solution at 25°C

Cr2(SO4)3, 1.26 mol/L, 1.37 mol/kg

Calculate the mole fraction, density and % w/w

## Homework Equations

χ = n Cr2(SO4)3 / n Cr2(SO4)3 + n H2O

Unit conversions

ρ= g solvent / mL solution

% w/w = mass solvent / 100 g solution

## The Attempt at a Solution

I attempted to solve for density first:

1.26 mol/L x 391.992g/mol x 1 L / 1000 mL = 0.493g/mL (The actual answer is 1.41g/mL)

Without density I do not know how to figure out the mole fraction. I am stuck at this part so far.

Thank you in advance.