Consider the following aqueous solution at 25°C
Cr2(SO4)3, 1.26 mol/L, 1.37 mol/kg
Calculate the mole fraction, density and % w/w
χ = n Cr2(SO4)3 / n Cr2(SO4)3 + n H2O
ρ= g solvent / mL solution
% w/w = mass solvent / 100 g solution
The Attempt at a Solution
I attempted to solve for density first:
1.26 mol/L x 391.992g/mol x 1 L / 1000 mL = 0.493g/mL (The actual answer is 1.41g/mL)
Without density I do not know how to figure out the mole fraction. I am stuck at this part so far.
Thank you in advance.