Calculate NaCl Concentration after Dilution

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SUMMARY

The final NaCl concentration after adding 2 µL of 50 mM NaCl to a 30 µL reaction is calculated to be 3.125 mM, which is equivalent to 3.125 x 10-3 M. The dilution factor is determined to be 1/16, derived from the ratio of the added volume to the total volume. The calculation process involves multiplying the dilution factor by the initial concentration and converting the result from millimolar to molar units. This method accurately reflects the principles of dilution in solution chemistry.

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Homework Statement


Addition of 2uL of 50mM NaCl to a 30 uL reaction gives a final NaCl concentration of ______ M.


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The Attempt at a Solution



so because you add 2uL to 30uL, the dilution is (2 / 2+30) = 1/16
Then I multiplied the dilution with the concentration for the new concentration
1/16 x 50mM = 3.125 mM

Finally, I converted the mM back to M
3.125 mM (1mol / 1000mmol)
answer = 3.125 x 10^-3M

does this look ok?

thank you in advance
 
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